Question
In the binomial expansion of $(a-b)^{n}, n \geq 5$, the sum of $5^{\text {th }}$ and $6^{\text {th }}$ terms is zero, then $\frac{a}{b}$ equals (A) $\frac{5}{n-4}$(B) $\frac{6}{n-5}$(C) $\frac{n-5}{6}$(D) $\frac{n-4}{5}$
Step 1
Step 1: The binomial expansion of $(a-b)^{n}$ is given by \[ (a-b)^{n} = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} (-b)^{k} \] Show more…
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