Question
In the binomial expansion of $(a-b)^{n}, n \geq 5$, the sum of the $5^{\text {th }}$ and $6^{\text {th }}$ terms is zero. Then $a / b$ equals(a) $(n-5) / 6$(b) $(n-4) / 5$(c) $5 /(n-4)$(d) $6 /(n-5)$
Step 1
The 5th term in the expansion is ${n \choose 4}a^{n-4}(-b)^4$ and the 6th term is ${n \choose 5}a^{n-5}(-b)^5$. Show more…
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