00:01
So in this problem, we have a circuit, and when we have a circuit like this and we're looking for the currents that are flowing through the different branches, what we're going to do is we're generally going to use kirkov's loop theorem as well as the junction rule in order to set up a system of equations to then solve for the unknowns.
00:17
So in this case, we have four unknowns that we're looking for.
00:20
We have i1, i2, r3, and i4, and these are directions that are picked arbitrarily for now.
00:28
We'll see in the calculations if we get a negative, or positive number as to whether these directions are correct.
00:35
So what we're first going to do is we're going to set up our four equations since we have four unknowns.
00:40
So we'll apply the loop rule to these three loops, the left, the middle, and the right, as well as the junction rule for our last fourth equation.
00:48
So when we do this, what we're going to get is these four equations.
00:55
So starting with the left loop, we'll have negative 200 times i1, minus 40, plus 80 times i2 equal to 0.
01:13
Then in the middle loop we'll have minus 80 times i2 plus 40 plus 360 minus 20 times i3.
01:31
And for the right loop we'll have 360 minus 20 times i3, minus 70 times i4 plus 80 and this expression is equal to 0.
01:53
And for the junction rule, we can see that we have i1 plus i2 plus i4 equal to i3.
02:03
Since we're considering this part here to be the junction that all the currents are flowing into.
02:12
So now that we have our system of equations, we're essentially just going to use algebra to eliminate and substitute in order to find the value of the currents.
02:21
So what we can first do is we'll go ahead and just label all these equations.
02:25
So we have 1, 2, 3, and 4...