00:07
This question asks us how we can synthesize each of these molecules, starting with f -vine.
00:13
So to start off, we need to look at where the triple bond ends up in the molecule, which would be right here.
00:21
And so we've added one carbon to this side and one, two, three, four, five carbons to that side.
00:27
So to do that, we're going to start off by doing that.
00:29
So first we'll add sodium amid, and then we will add an alkyl halide.
00:37
So i'm going to use ch3br here that matches the number of carbons you want to add to whatever side.
00:43
So that one gave us that methyl group on that side.
00:48
And then we'll do it again to get the other side.
00:53
How many? so that was one, two, three, four, five.
00:57
So one, two, three, four, five, and then a bromine...