Question
Show that 5 is a critical number of the function$$g(x)=2+(x-5)^3$$but $g$ does not have a local extreme value at 5 .
Step 1
The derivative, \( g'(x) \), is found using the power rule. \[ g'(x) = \frac{d}{dx}[2 + (x-5)^3] = 0 + 3(x-5)^2 = 3(x-5)^2. \] Show more…
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Show that $5$ is a critical number of the function $$ g(x) = 2 + (x - 5)^3 $$ but $g$ does not have a local extreme value at $5$.
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