Show that current conservation at the hadronic vertex requires
$$
q_{\mu} W^{\mu \nu}=q_{\nu} W^{\mu \nu}=0
$$
The proof may be left until after (8.39); it follows from $\partial_{\mu} \tilde{J}^{\mu}=0$. As a result of (8.26), verify that
$$
\begin{aligned}
&W_{5}=-\frac{p \cdot q}{q^{2}} W_{2} \\
&W_{4}=\left(\frac{p \cdot q}{q^{2}}\right)^{2} W_{2}+\frac{M^{2}}{q^{2}} W_{1}
\end{aligned}
$$
Thus, only two of the four inelastic structure functions of (8.24) are indepenlent; so we may write
$$
W^{\mu \nu}=W_{1}\left(-g^{\mu \nu}+\frac{q^{\mu} q^{\nu}}{q^{2}}\right)+W_{2} \frac{1}{M^{2}}\left(p^{\mu}-\frac{p \cdot q}{q^{2}} q^{\mu}\right)\left(p^{\nu}-\frac{p \cdot q}{q^{2}} q^{\nu}\right),
$$
where the $W_{i}$ 's are functions of the Lorentz scalar variables that can be constructed from the four-momenta at the hadronic vertex. Unlike elastic scattering, there are two independent variables, and we choose
$$
q^{2} \quad \text { and } \quad \nu \equiv \frac{p \cdot q}{M} .
$$
The invariant mass $W$ of the final hadronic system is related to $\nu$ and $q^{2}$ by
$$
W^{2}=(p+q)^{2}=M^{2}+2 M \nu+q^{2} .
$$