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Good day.
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A photon has a certain energy which can be solved in terms of its wavelength as e equals hc over lambda, where e is the energy in jules.
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H is the flux constant, which value is equal to 6 .626 times 10 to the negative 4 joules 2.
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C is the speed of the photon, which is a particle of light, so it travels at the speed of light, which is 3 times 10 to the 8 meters per second, and lambda is the wavelength in meters.
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In this case, even with a photon that has a wavelength of 1 ,240 nanometer, we wish to show that its wavelength, or rather its energy, is indeed equal to one electron volt.
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So to solve for that, we have e equals h, which is 6 .626 times 10 to the negative 34 times c, which is 3 times 10 to the power of 8 over lambda, which must be in terms of meters.
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So we have here nanometers...