Question
Show that the tangent to the curve $y=\left(x^{2}+x-2\right)^{3}+3$ at the point (1,3) is also the tangent to the curve at another point.
Step 1
We use the chain rule to differentiate the function $y=\left(x^{2}+x-2\right)^{3}+3$. The derivative of the function is given by: \[y' = 3\left(x^{2}+x-2\right)^{2}(2x+1)\] Show more…
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