00:01
Okay, for this question, we want to show that the time rate of change of mechanical energy for a damped undruined oscillator is given by dedt is equal to minus bv squared.
00:12
And what we're given is the mechanical energy for this type of oscillator, one half mv squared plus one half kx squared.
00:20
And it tells us to use this equation 15 .31, which is given here in green, which is as follows.
00:28
Minus k x minus b the x d x d t is equal to m times the second derivative of x with respect to t so i've kind of already started off this question so we have the mechanical energy for a damp undripen oscillator as follows we're going to take the time derivative of this equation to get started and get hopefully the result they wants to show so the tricky thing here is doing this uh derivative with respect to time is dealing with the quantities v and x because yes they're with respect to time but also they also relate to position right so this is where where i already put in red we want to use implicit differentiation that's the key here for this problem so we want to treat it as yeah we're going to take the time derivative of velocity and x but that term those respective terms velocity in position v and x are still going to be there after we do the chain rule here as we differentiate.
01:34
So i kind of just write it out and show you what that means or what it looks like.
01:38
I'm sure you guys have looked at it before, but that can be kind of tricky with this type of problem is knowing when to just straight out, take a derivative or when to use implicit differentiation.
01:50
We're dealing with these more abstract variables.
01:55
Okay, so we're going to do time derivative of one half mb squared.
01:59
So we have the chain rule.
02:00
So that's going to be, let's just write this out first.
02:03
We have one half m.
02:05
Those have nothing to do with time.
02:07
Those are dependent of time.
02:09
Or i'm sorry, independent of time.
02:12
So now we're just taking the derivative of v squared with respect to time.
02:17
So chain rule.
02:18
So we have times 2v.
02:22
That's why i mean by implicit differentiation is 2v times you can use v prime, v.
02:28
Dot, or you can use dv, d t for the sake of making things.
02:33
Look nice, we'll do v.
02:36
Dot for that time derivative.
02:38
Okay, now we're gonna do the time derivative of 1 half k x squared...