In $\left[\mathrm{MnF}_{6}\right]^{2-}$, each F has a charge of -1, so the Mn must have a charge of +4 to balance the overall -2 charge. In $\left[\mathrm{Mn}(\mathrm{CN})_{6}\right]^{3-}$, each CN has a charge of -1, so the Mn must have a charge of +3 to balance
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