00:01
All right, here we have a nice modeling question.
00:06
We have a model for the depth of water at hopewell cape.
00:11
The depth you can see here is this kind of trig expression.
00:17
The depth is in meters and the time is in hours.
00:20
And we want to find the rate of change at different times.
00:24
So let's first go ahead and find the rate of change, which is the derivative, and then we'll plug in our values.
00:31
So, um, uh, whoops.
00:35
Okay, so we're finding the derivative.
00:37
The derivative of seven is zero.
00:39
So zero plus five goes along for the ride.
00:43
The derivative of cosine is minus sign.
00:46
We have a big chain roll.
00:48
So at first with chain roll, when you have a composite, you take the derivative of the outer function and you leave the entire argument the same.
00:57
So let's go do that.
01:04
Okay.
01:04
Then we multiply by the derivative of the inside argument and the derivative of the inside argument is 0 .503 coming along for the ride and the derivative of t minus 6 .75 is just one minus zero or one.
01:22
Okay, so let's clean this up.
01:24
D prime of t then is going to be equal to minus five times, oops, actually i need to multiply.
01:34
Let's get this all cleaned up.
01:37
We have a minus 5 and a .503.
01:44
So let's multiply that out.
01:46
That will give us minus 2 .215 sign of 0 .503 t minus 6 .75.
02:03
Okay, so that is a rated change of depth and meters with time.
02:09
And time, by the way, starts at t0 is midnight.
02:15
T is zero hours is midnight.
02:23
Okay, and we'll need that when we find a specific time.
02:26
So just a reminder, we definitely need that.
02:30
Okay, so really all we have left to do is plug in for t the different times they gave us.
02:38
So let's go ahead and i'm going to set this up.
02:41
I'm going to show you the result.
02:42
I'm not going to be right it each time because it will be very repetitive.
02:47
Our times of interest are 3 a .m...