We have the wavelength of light, \( \lambda = 476 \, \text{nm} = 476 \times 10^{-9} \, \text{m} \), the width of the central bright fringe, \( W = 2.0 \, \text{cm} = 0.02 \, \text{m} \), and the distance from the slit to the screen, \( L = 1.05 \, \text{m} \).
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