00:01
In this question, we have a simplified circuit for a photographic flash unit.
00:07
The circuit consists of a battery, a resistor, and a capacitor, whose values we are aware of, as well as two switches.
00:17
We are asked to calculate the time it takes for the capacitor to charge to a voltage of five volts once the first switch is closed.
00:31
Now, we do have a formula for this type of circuit.
00:34
Once switch one is closed, we have a very typical rc circuit, and we do have a formula for the charge on the capacitor as a function of time.
00:51
But in order to use this formula to get at the time that we're interested in, we're going to need to know what the charge is, the corresponding charge is at that time.
01:00
Now, we know that the capacitance is 140 microferods, and we also know that we want that to be charged to a voltage of 5 volts at the time that we're considering.
01:15
So what we can do is take the capacitance and the voltage and calculate the corresponding charge.
01:22
So the charge on the capacitor at the time we're interested in is going to be c times v, 140.
01:34
Microfarads times five volts.
01:38
And so that's gonna give us a value of 700 microculems.
01:44
So basically this problem is equivalent to asking how long does it take for the capacitor to be charged to a charge of 700 microculems? so we're just gonna take that formula that we have for this and seven the values that we have.
02:04
So the capacitance is 140 micro ferats.
02:11
The emf or the voltage on the battery is 9 volts.
02:19
And then we have 1 minus e to the minus t over tau.
02:25
Now, tau is the time constant.
02:28
That's going to be r times c.
02:30
So let's just do a quick calculation of that on the side...