Question
The common tangents to the circle $x^{2}+y^{2}=2$ and the parabola $y^{2}=8 x$ touch the circle at the points $P, Q$ and the parabola at the points $R, S$. Then, the area (in sq units) of the quadrilateral $P Q R S$ is
Step 1
The circle is given by \( x^2 + y^2 = 2 \) and the parabola is given by \( y^2 = 8x \). Show more…
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The common tangents to the circle $x^{2}+y^{2}=2$ and the parabola $y^{2}=8 x$ touch the circle at the points $P, Q$ and the parabola at the points $R, S$. Then the area of the quadrilateral $P Q R S$ is (a) 3 (b) 6 (c) 9 (d) 15
Let $P Q$ and $R S$ be tangents at the extremeties of the diameter $P R$ of a circle of radius $r$. If $P S$ and $R Q$ intersect at a point $X$ on the circumference of the circle, then $2 r$ equals (A) $\sqrt{P Q \cdot R S}$ (B) $\frac{P Q+R S}{2}$ (C) $\frac{2 P Q \cdot R S}{P Q+R S}$ (D) $\sqrt{\frac{P Q^{2}+R S^{2}}{2}}$
Let $P Q$ and $R S$ be tangents at the extremities of the diameter PR of a circle of radius $r .$ If $P S$ and $R Q$ intersect at a point $X$ on the circumference of the circle, then $2 r$ equals (a) $\sqrt{P Q \cdot R S}$ (b) $(P Q+R S) / 2$ (c) $2 P Q \cdot R S /(P Q+R S)$ (d) $\sqrt{\left(P Q^{2}+R S^{2}\right)} / 2$
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