00:01
So firstly for this problem, we'll calculate the magnitude of the induced emf across the ends of the rod.
00:09
So epsilon, the adduced emf, is equal to v, the speed of the rod, times the strength of the magnetic field b, times the length of the rod l.
00:18
And these values are known.
00:21
So this is 7 .5 meters per second, or v, the magnetic field strength is given as 0 .8.
00:31
Tesla's and the length of the rod is 0 .5 meters.
00:38
And hence we get an induced emf of three balls.
00:48
Next we want to find the direction of the induced current.
00:54
Well we know that the magnetic field b is into the page.
01:00
So that's its direction.
01:01
The flux increases as the bar moves to the right.
01:04
So the magnetic field of the induced current is out of the page inside the circuit.
01:11
So the induced magnetic field will call it the induced or the magnetic field due to the induced current is out of the page.
01:22
To produce the magnetic field in this direction, the induced current must be in a counterclockwise direction.
01:33
And so that's from b to a in the rod.
01:48
Next we want to calculate the force that needs to be applied to provide this motion.
01:55
We know that the current i is equal to the induced emf epsilon divided by the resistance.
02:03
Again, both these values are known...