00:01
Okay, so we're going to chapter 29, problem 29.
00:05
So in this problem, we have a little bar here.
00:13
And this is all in a b field that is pointing into the page.
00:22
And they call this point c, this point d.
00:27
And along this, there is a bar.
00:34
And it is moving along at a velocity v in this direction.
00:42
It also tells us the length here is 50 centimeters and magnitude of b is 0 .8 tesla.
00:59
Okay, so it says part a, find the magnitude of the emf induced in the rod when it is moving towards the right with a speed of 7 .5 meters per second.
01:13
So v equals 7 .5 meters per second.
01:17
So we want to use the equation here we've been using that the emf is the miss.
01:28
And we know that the b field and v are 90 degrees apart, so this is all the equation we need.
01:33
We don't need to use the sign part.
01:37
So we know that this is going to give us 7 .5 meters per second times 0 .8 tesla times 0 .5 meters.
01:49
This is 3 .0 volts.
01:57
So now for part b it says, in what direction does the current flow in the rod? so we know that b is into the page, and as it moves to the right, a gets bigger, right? the area, because this is our loop right here, this is our loop.
02:18
The a is getting bigger, the b is constant.
02:21
So that means our flux b is into the page, and it's increasing.
02:28
So using the lenses law, the induced b must be out of the page.
02:36
Okay, so now using the right -hand rule, does a counterclockwise or clockwise point it out of the page? you'll do that and you'll find it's counterclockwise.
02:49
So that means in the rod, if this is moving counterclockwise, it's moving from b to a...