00:01
In this question, given, the index of refraction of benzene is 1 .8.
00:14
We want to find a critical angle, okay, when the light ray travels, traveling in the benzene, travels toward the air, the benzene air boundary.
00:28
Okay, so like this, right? so we're using...
00:47
Using snells law, we say that n1, sine data 1 equals to n2, sine data 2.
00:59
So data 1 is the critical angle, n2 is 1 .0, n1 is 1 .8, and then data 2 is 90 degrees...