00:01
So drawing the two free body diagrams, we have mass lowercase m.
00:05
Here going straight up would be the static frictional force, going straight down to be m g.
00:12
To the right would be the force applied.
00:17
And to the left we have force prime.
00:21
We have then the larger mass capital m going straight down would of course be the gravitational force capital m.
00:32
To the right f prime and going up force normal so given this we can say that f prime would be the contact force between the two blocks and we know that here you can say the static frictional force would be equaling the maximum static frictional force equaling the coefficient of static friction multiplied by f prime where here the coefficient of static friction equaling 0 .38.
01:08
Treating the blocks together as a single system, we can apply newton's second law where the f mass, the force applied is equaling the mass total, multiplied by the acceleration, where the acceleration would be equaling f over m plus m.
01:27
And so we can say that, analyzing these two blocks separately now, we can apply newton's second law, and we can say that f minus f prime equaling the mass times the acceleration...