00:01
In this exercise, we have a quantum particle that's confined to a box of length l, and we are given the information that the allowed values for the wavelength of this particle are those that result in standing waves with nodes at the two ends of the box.
00:22
And in question a, we have to show that an electron that is confined to a box of length l has an energy that is equal to.
00:33
H -bar -squared and squared divided by 8 times the mass of the electron times l squared.
00:42
So first, let's start with the dabburly formula.
00:47
So we have that p is equal to h divided by lambda.
00:51
This is the deberlea formula for the momentum of any particle.
01:00
And this is equal to mv.
01:02
Okay, for a massive particle, the momentum is equal to mv.
01:08
Also, we have that the energy of the electron, the kinetic energy, is mv squared over 2.
01:17
I'll notice that we can write the speed v in terms of lambda as h divided by m lambda.
01:28
So e is equal to m divided by 2 times h over h over a.
01:44
M lambda squared.
01:46
So this is equal to age squared divided by 2 m lambda squared...