344 \mathrm{~A}$, the cross-sectional area $A = 1 \mathrm{~mm}^{2} = 1 \times 10^{-6} \mathrm{~m}^{2}$, and the number of free electrons per unit volume $n = 8.4 \times 10^{22} \mathrm{~cm}^{-3} = 8.4 \times 10^{28} \mathrm{~m}^{-3}$. We are asked to find the drift
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