00:01
Hello, my name is david.
00:02
In this video, we'll cover the angular acceleration of a solid sphere and a holosphere.
00:07
So for this problem, we have a thin spherical shell and a solid sphere both rotating with an initial angular velocity of 24 rats per second.
00:21
And both of them have a radius of 0 .20 meters with a mass of 1 .5 kilograms.
00:31
And suddenly an external torque due to friction starts to slow them down.
00:37
And this torque is equal to negative 0 .12 newton's meter.
00:44
So for the first part, we want to know which sphere has the moment of inertia with the greater magnitude.
00:53
So the moment of inertia for a solid sphere is equal to two fits times the mass times the radius square and the moment of inertia for a holosphere or a thin walled spherical shell is equal to two thirds times the mass times the radius square.
01:17
So the thing wall spherical shell has the greater moment of inertia.
01:28
Now for the second part, we want to know which of these spheres has the angular acceleration with the smaller magnitude.
01:38
So we know that the net torque is equal to the moment of inertia times the angular acceleration.
01:48
But since we only have one torque acting on the spheres, which is the external torque due to friction.
01:54
We get that the external torque is equal to the moment of inertia times the angular acceleration.
02:02
So we saw for the angular acceleration, we get that the angular acceleration is equal to the external torque divided by the moment of inertia.
02:13
So for a solid sphere, we get that the angular acceleration is equal to the external torque divided by two feet, mr square.
02:31
So with plug in our values, we get negative 0 .12 newton meters divided by two fits times 1 .5 kilograms times 0 .2 meters squared.
02:50
So we clean it up, we get negative 0 .12 newton's meter divided by 0 .024 kilograms meter square...