Question
Use (5.41) to show that$$\bar{u}^{(s)} u^{(s)}=2 m, \quad \bar{v}^{(s)} v^{(s)}=-2 m$$
Step 1
The notation \( \bar{u}^{(s)} u^{(s)} \) represents the inner product of the spinor \( u^{(s)} \) with its adjoint \( \bar{u}^{(s)} \). Similarly, \( \bar{v}^{(s)} v^{(s)} \) represents the inner product of the spinor \( v^{(s)} \) with its adjoint \( Show more…
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