Question
Use the circuit shown in Fig. $12.29 .$ The current in the circuit is $5.75 \mathrm{mA}$. Determine the indicated quantities.In The voltage across the resistor (between points $a$ and $b$ ).
Step 1
We do this by multiplying the given current by $10^{-3}$ because 1 milliampere equals $10^{-3}$ amperes. So, the current $I$ in amperes is $5.75 \times 10^{-3}$. Show more…
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