What are the products of the following reactions?

Name: Problem 60, Chapter 7: Organic Chemistry
Uploaded: 2020-07-27T18:25:38-08:00
Duration: 4 min 15 s
Channel: Madeline Currie
Description: What are the products of the following reactions?

Key Concepts

Chemical Reaction

A chemical reaction is a process in which reactants are transformed into products through the breaking and formation of chemical bonds. Understanding this concept is fundamental because it underpins the transition from starting materials to final products in any chemical equation.

Reaction Mechanism

The reaction mechanism refers to the sequence of elementary steps that occur during a chemical reaction. It explains how reactants are converted into products by detailing the formation and breaking of bonds, intermediates, and transition states, which is crucial for predicting the final products.

Predicting Reaction Products

Predicting the products of a reaction involves using knowledge of chemical reactivity, reaction mechanisms, and the properties of the reactants. This concept entails analyzing the type of reaction taking place, potential intermediates, and the stability of possible products to determine the most likely outcomes.

Balancing Chemical Equations

Balancing chemical equations is a key concept in chemistry that ensures the conservation of mass and charge in a reaction. It involves adjusting the coefficients of reactants and products so that the number of atoms for each element is the same on both sides of the equation, which is essential for accurately representing any chemical reaction.

Transcript

00:08 This question asks us for the products of each of these reactions.

00:12 So starting with a, if we have an excess of cl2, for each pie bond, we'll add a chlorine to each carbon.

00:20 So we have two pie bonds, so each carbon gets two chlorines.

00:23 So we'll have two chlorines on this side, two chlorines on this carbon, and then we'll have the rest of that molecule.

00:35 If we have just one equivalent of chlorine, then we'll get an alkene.

00:40 And chlorine adds anti, so we get a transalkene.

00:43 So if we have that c, we'll have a chlorine up and down on the other side.

00:49 And then we will have the rest of that molecule over there.

00:55 If we have water, acid, and the mercuric ion with the terminal alkyne, that will give us acid catalysis hydration.

01:04 So we're going to end up adding an oh to one of these carbons.

01:09 And because this one will give us a more stable carbocadion, that is the one that's going to get the oh on it.

01:15 So first we'll get an enol that will look like this.

01:22 And then that will totomerize into a ketone that will look like that.

01:30 Okay.

01:31 And then for d, now we have that same alkyne, but now we're doing hydroboration oxidation on it.

01:37 So instead of attacking the more substituted carbon with the oh, we're going to end up with the oh on the less substituted carbon.

01:45 So our enol will look a little bit different.

01:47 It'll look like this.

01:52 And then when we tetamorize, we'll get an althahide instead of the ketone that we had before.

01:58 So it'll look like that.

02:05 There is our aldehyde.

02:08 In e, we have an alkyne with h2 and palladium.

02:12 And that will reduce it all the way to.

02:14 An alcan...

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