What is the mass of solute in each of the following...

What is the mass of solute in each of the following solutions? (a) 1.00 L of $0.100 \mathrm{M} \mathrm{NaOH}$ (b) $1.00 \mathrm{~L}$ of $0.100 \mathrm{M} \mathrm{LiHCO}_{3}$ (c) $25.0 \mathrm{~mL}$ of $0.500 \mathrm{M} \mathrm{CuCl}_{2}$ (d) $25.0 \mathrm{~mL}$ of $0.500 \mathrm{M} \mathrm{KMnO}_{4}$

What is the mass of solute in each of the following solutions?
(a) 1.00 L of $0.100 \mathrm{M} \mathrm{NaOH}$
(b) $1.00 \mathrm{~L}$ of $0.100 \mathrm{M} \mathrm{LiHCO}_{3}$
(c) $25.0 \mathrm{~mL}$ of $0.500 \mathrm{M} \mathrm{CuCl}_{2}$
(d) $25.0 \mathrm{~mL}$ of $0.500 \mathrm{M} \mathrm{KMnO}_{4}$

Key Concepts

Molarity

Molarity is a measure of concentration that expresses the number of moles of solute per liter of solution. It is used to quantitatively describe the amount of solute in a given volume, making it essential for calculations involving solution concentrations.

Volume-to-Mole Conversion

This concept involves converting the volume of a solution into the number of moles of solute present by using the molarity. Multiplying the concentration (in mol/L) by the volume (in L) gives the number of moles, which is a crucial step in determining the mass of the solute.

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It enables the translation of the number of moles obtained from a volume-to-mole conversion into the mass of the solute by multiplying the two values together.

Transcript

00:01 In this question, we need to determine the mass of the solid that is in the specific solution with a given molar concentration.

00:13 Now, in number a, we work with one liter of a sodium hydroxide solution, and this solution has a molar concentration of 0 .1 -0 -0 molar.

00:26 So if i need to calculate the mass of the solute, this is going to be in terms of grams.

00:41 So let's say grams of sodium hydroxide is what i want.

00:48 And i start off with the specific volume of one liter of solution.

00:57 I'm going to put that over one.

01:02 And then i need to multiply it with something.

01:05 But this something should be something that helps to get rid of the liter unit here.

01:14 And i will therefore make use of one of the unit factors of the molar concentration that i've written down here in red.

01:23 So the question is which one of them will be the best to use in this situation? and it will be the first one because in the first one i have one liter solution here at the bottom.

01:37 So this will cancel the liter solution in my first factor out.

01:44 So i've got 0 .10 .10 .0 moles of sodium hydroxide here at the top.

01:53 But now if you look at the units and the...

01:58 Liter solution cancels out.

02:01 I still have moles here.

02:03 Now i need to get rid of the number of moles and i can do that by multiplying by the molar mass of sodium hydroxide.

02:11 So this will be 40 grams of sodium hydroxide per one mole of sodium hydroxide.

02:21 And here it's clear now that i end up with some value in terms of grams.

02:31 So let's quickly do this calculation.

02:34 This gives me a value of 4 .00 grams of sodium hydroxide.

02:45 Right.

02:46 So this is the mass of solid involved in this solution.

02:52 Right.

02:53 In number b, number b is basically the same procedure that we're going to use here.

02:58 So we want the mass of lithium hydrogen carbonate in terms of grams.

03:08 We start off with a volume of one liter of this specific solution.

03:16 So i'll put this over one again.

03:20 And then i need to choose the appropriate unit factor here with regard to the molar concentration.

03:28 And i'm going to choose the first one so that the liter solution can cancel out.

03:35 So it's 0 .10 0 moles of lithium hydrogen carbonate over 1 liter of solution.

03:50 And here you can see that the liter of solution will cancel out.

04:01 And now you need to realize that you still have to multiply.

04:06 With molar mass here so that we can get rid of the number of moles.

04:11 So the molar mass of lithium hydrogen carbonate is 67 .96 grams...

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