00:01
In this question, we need to determine the malarity of sodium hydroxide, which reacts with nitric acids.
00:10
Both volumes of these reagents are provided, as well as the molarity of nitric acid.
00:20
And the calculation needs to be done according to the reaction equation, which is given in the question, and also present it on this page.
00:31
All right.
00:32
So for us in order to calculate molarity, we know that this is moles per liter.
00:43
So we need to calculate a number of moles of sodium hydroxide.
00:48
And we already have the volume, even though in milliliters, we can just convert that to liters.
00:55
So first of all, we will need to calculate a number.
01:00
Number of moles of sodium hydroxide and this we will calculate from the number of moles of nitric acid and then yes just use this stoichiometric ratio to calculate the number of moles of sodium hydroxide and from there we can easily then calculate the molarity right so our first step is to calculate the number of moles of sodium nitroxide.
01:32
So, oh, sorry, not sodium nitric acid.
01:40
We have the volume in terms of milliliters.
01:44
So we need to convert that to liters because we're going to multiply that with the molarity of nitric acid, which is in terms of moles per litre.
01:57
So this is 0 .0 .0342 moles per 1 litre.
02:08
Right, and if we do that, you can also see that the units cancel out and we end up with moles.
02:15
Now i'm not going to do the calculation here...