The deuterium in $\mathrm{D}_{2} \mathrm{SO}_{4}$ acts as an electrophile, which can react with the benzene ring.
\[
\begin{array}{c}
\mathrm{C}_{6} \mathrm{H}_{6}+\mathrm{D}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{D}+\mathrm{H}_{2}
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