00:01
Okay, so this is a limiting reactant problem, and we know that's true because we're given amounts of both reactants.
00:07
So the first thing we're going to do is try to figure out who's our limiting reactant.
00:12
So what i'm going to do is i'm going to take the mass of the copper 2 oxide, which is 38 .72 grams, and i'm going to take the 5 .67 liters of h2, and i'm basically going to do the problem twice and figure out, how many grams of copper would be formed.
00:38
And whichever one is smaller will be our limiting reactant.
00:42
Okay, so i'm going to change grams of cuo to moles of cuo.
00:49
I picked copper because they're asking us about copper in the next part.
00:54
So moles of coo to moles of cu.
00:59
Okay.
00:59
And then moles of copper to grams of copper.
01:05
Okay, so one mole of cuo is 79.
01:10
0 .55 grams.
01:12
Our mole ratio is 1 to 1, and 1 mole of copper is 63 .55.
01:19
So if copper 2 oxide is our limiting reactant, we'll be able to make 30 .93 grams of copper.
01:31
So here i've got liters, but they've given me a density.
01:35
So i'm going to go ahead and change liters to grams of my hydrogen.
01:40
And then i'm going to change my grams of hydrogen to moles of hydrogen so i can do a mole ratio.
01:48
So i'm going to change moles of h2 to moles of copper.
01:54
And then again, i'm going to change moles of copper to grams of copper.
02:00
Okay, so 63 .55.
02:05
My mole ratio here is again going to be one to one.
02:11
This is diatomic, so 2 .02.
02:13
And the density they gave us was 0 .0519 grams per liter...