00:01
All right, so what is the net charge of the tripeptide glycerglyarglis at ph 7 .0? p .ks of the ionizable groups on the free amino acids are for glycline, you have 2 .4 and 9 .8.
00:18
9 .0 and 12 .5.
00:21
And for lysine is 2 .2, 9 .1, and 10 .5.
00:25
And then we have the answers either negative 2, negative 1 ,0, plus 1, or plus 2.
00:30
So the general rule of thumb to follow, to solve a given problem is as follows.
00:36
So at ph less than p .k .a means h -plus ions are on, and it becomes pro -donated.
01:00
So at ph where it is greater than p -k -a means the h -plus ions are on, ions are off and it becomes deprotonated.
01:20
So using that we can take a look at glycine first.
01:26
So for glycine we have the pk value or the pca value of the alpha carboxylic group is smaller than the ph so if we have ph 7 this is greater than the pca of 2 .4 and also with the other part, the value of the alpha amino group is greater than ph.
01:59
So we have ph 7 is less than p -k -a equal 9 .8.
02:07
So with this first one up here being less than, it will become deprotonated.
02:19
And with this being greater, this will be protonated.
02:23
So therefore, both charges neutralize each other.
02:45
So the net charge on the amino acids would be zero.
02:56
So now moving on to argonine.
03:04
So we have ph 7 again and then pca of 1 .8.
03:12
So ph 7 will be greater, 1 .8.
03:20
So this would be deprotonated.
03:21
Again, at ph 7, we have is less than pca of 9 .0.
03:45
This would be protonated, but the pca of the side chain is greater than the ph, which is 12 .5...