6.22. Consider steady-state operation of a chemostat. Assume that growth is substrate inhibited and that endogenous metabolism can be ignored such that we get the following: mu_{net} = frac{mu_m S}{K_S + S + S^2/K_I} a. Derive an expression for the residual substrate concentration (i.e., S) as a function of dilution rate and the kinetic parameters (mu_m, K_S, K_I). b. What are the implications for operation of a chemostat when the organism is subjected to substrate inhibition?
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Step 1: Identify the given equation for the net specific growth rate (\(\mu_{\text{net}}\)) in the chemostat: \[ \mu_{\text{net}} = \frac{\mu_m S}{K_s + S + \frac{S^2}{K_I}} \] Show more…
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