A 440V dc shunt motor takes an armature current of 60A when its speed is 750 rpm. Determine the torque developed in the armature if the armature resistance is 0.25Ω. 189.56 N-m 341.82 N-m 324. 68 N-m 212.45 N-m
Added by Nathaniel O.
Step 1
The voltage drop across the armature resistance (I_a * R_a) is the product of the armature current (I_a) and the armature resistance (R_a). Given: - Total supplied voltage (V) = 440V - Armature current (I_a) = 60A - Armature resistance (R_a) = 0.25Ω Calculate Show more…
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