Question

OD\textsubscript{SDS} Standard Curve for Bradford Assay y = 0,2409x + 0,2298 R\textsuperscript{2} = 0,9835 Dikey (De?er) Eksen Birincil K?lavuz Çiz

          OD\textsubscript{SDS}
Standard Curve for Bradford Assay
y = 0,2409x + 0,2298
R\textsuperscript{2} = 0,9835
Dikey (De?er) Eksen Birincil K?lavuz Çiz

ODSDS
Standard Curve for Bradford Assay
y = 0,2409x + 0,2298
R2 = 0,9835
Dikey (De?er) Eksen Birincil K?lavuz Çiz

Added by Tracy H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Suman K

05/03/2022

Step 1

125 mg/ml = 0.2489*(0.3145-0.2298)/0.2298 = 0.125 mg/ml BSA 0.125 mg/ml = 0.2489*(0.3245-0.2298)/0.2298 = 0.125 mg/ml BSA 0.25 mg/ml = 0.2489*(0.3345-0.2298)/0.2298 = 0.25 mg/ml BSA 0.25 mg/ml = 0.2489*(0.3385-0.2298)/0.2298 = 0.25 mg/ml BSA 0.5 mg/ml = Show more…

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Bradford Assay experiment is done. The following table shows the loading order, and table 2 shows the absorbance values. The standard curve is also found as shown below. From these values, calculate the concentration of the pellet and supernatant. BSA 0.125 mg/ml BSA 0.125 mg/ml BSA 0.25 mg/ml BSA 0.25 mg/ml BSA 0.5 mg/ml BSA 0.5 mg/ml BSA 1 mg/ml BSA 1 mg/ml Blank Blank Unknown Unknown 0% Salt Supernatant 1:50 0% Salt SP 1:50 0% Salt SP 1:100 0% Salt SP 1:100 0% Salt Pellet 1:50 0% Salt Pel 1:50 0% Salt Pel 1:100 0% Salt Pel 1:100 0.3145 0.3245 0.3345 0.3385 0.398 0.452 0.498 0.55 0.057 0.06 0.491 0.512 0.646 0.451 0.343 0.287 0.217 0.194 0.18 0.226 Standard Curve for Bradford Assay = 0.2489* + 0.2298 R^2 = 0.9835 0.5 0.45 0.4 0.35 0.3 0.25 0.2 0.15 0.1 0.05 Dikey (Deger) Eksen Birincil Kilavuz Ciz 0.2 0.4 0.6 ug BSA 0.8 1.2