Find the equation of the tangent line to the curve y = x8 + 2ex at the point (0, 2).
Added by Mary M.
Step 1
The derivative of x^8 is 8x^7, and the derivative of 2e^x is 2e^x. Therefore, the derivative of the curve y = x^8 + 2e^x is: y' = 8x^7 + 2e^x Show more…
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