00:01
In this question, even the position function of particle, we are asked to find the formula for its velocity, to find its velocity at x equals 0 and x equals 2, and find the values of x where its velocity equals to 0.
00:16
So, to answer the first question, we're basically given the formula already.
00:21
We just need to define the velocity, we need to differentiate the function f.
00:27
And we're asked to find the derivative of the function to 70x minus 18 x squared.
00:34
And to differentiate this function, we are simply going to use the power roll.
00:40
The derivative of 270x equals to 270 and the derivative of x squared equals to 2x.
00:56
We are going to get 270 minus 36x.
01:02
So this is v of x, velocity of the particle.
01:09
The formula is v of x equals to 270 minus 36x.
01:14
Now let's find the values of v at 0 and 2.
01:20
Of 0 equals to 270 minus 36 times 0 and equals to 270 and view of 2 equals to 270 and velocity at 270 minus 72 and equals to 198.
01:52
So velocity at 0 is to 70 and velocity at x equals 2 is 198.
01:57
So it's decreasing.
01:59
And let's answer the last question.
02:02
We are asked to find the points, the values of x, at which v.
02:06
Of x equals to 0.
02:08
So we just need to solve the equation v of x equals 0...