Given s(t) = 3t^2 + 12t, where s(t) is in feet and t is in seconds, find each of the following. a) v(t) b) a(t) c) The velocity and acceleration when t = 2 sec a) v(t) = b) a(t) = c) When t = 2 sec, the velocity is ft/sec. (Simplify your answer.) When t = 2 sec, the acceleration is ft/sec^2. (Simplify your answer.)
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To find the velocity function v(t), we need to take the derivative of s(t) with respect to t: v(t) = s'(t) Using the power rule of differentiation, we get: v(t) = 347(2t)^(1/2) = 694t^(1/2) b) Show more…
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