00:01
In this question, we are asked to find the local maxima, the local minima, and the subtle points of the function f.
00:06
To do that, we need to solve the system of equations fx equals 0 and fy equals 0 to find the critical points.
00:17
This is a system of equations for finding critical points.
00:20
And then, we will use the critical points to find the absolute extrema and the subtle points.
00:27
In our case, the derivative of f with respect to x equals to 2x minus, 6y and we want it to be equal to 0 the derivative of f with respect to y equals to negative 6x plus 2y plus 16 and we also want it to be equal to 0 all right now this is a system of linear equations the first equation could be divided we could divide we could divide we can divide the first equation by 2 we are going to get x minus 3 y equals to 0 and the second equation could be also divided by 2 we are going to get negative 3x plus y plus 8 equals 0 now we are going to from the first equation x equals to 3y now we are going to plug in x equals to 3y in the second equation we are going to get negative 3 multiplied by 3y plus y now let's move 8 to the right hand side to get negative 8 on the right side negative 3 times 3 y is negative 1 negative 9y negative 9y plus y equals to negative 8y.
01:48
So in the second equation, we are going to get negative 8 y equals to negative 8.
01:54
And in the first equation, x equals to 3y.
02:00
Then y equals to 1.
02:02
And after plugging in y equals 1 in the first equation, we are going to get that x equals 3.
02:07
So this is the only critical point of our function.
02:16
Now we will use the second derivative test.
02:26
By the second derivative test, we need to calculate the quantity called d of xy.
02:31
Which equals to f double x multiplied by f double y minus f x y squared.
02:40
Where f double x is the second derivative of f with respect to x, recall that the first derivative equals to 2x minus 6y.
02:50
And if we differentiated one more time with respect to x, we are going to get 2.
02:56
F double y equals to the second derivative of f with respect to y, recall that the first derivative equals to negative 6x plus 2y plus 16.
03:06
So if we differentiate it one more time with respect to y, we are going to get 2.
03:13
And fxy is the derivative of fx with respect to y...