Nitrogen monoxide and oxygen react to form nitrogen dioxide...

Nitrogen monoxide and oxygen react to form nitrogen dioxide. Consider the mixture of NO and O $_{2}$ shown in the accompanying diagram. The blue spheres represent $\mathrm{N},$ and the red ones represent $\mathrm{O}$ . (a) How many molecules of $\mathrm{NO}_{2}$ can be formed, assuming the reaction goes to completion? (b) What is the limiting reactant? (c) If the actual yield of the reaction was 75$\%$ instead of 100$\%$ , how many molecules of each kind would be present after the reaction was over?

Transcript

00:01 In this question, we're looking at nitrogen monoxide and water forming nitrogen dioxide.

00:07 And we need to figure out how much nitrogen dioxide we can make.

00:12 And also, what is the limiting reactant and stuff that happens if maybe the actual yield isn't as much.

00:18 So first, let's look at what is the reaction going on.

00:21 So we've got n -o and o2 reacting to form n -o, which is nitrogen monoxide.

00:28 Now you might look at this.

00:30 Sorry i should dioxin there's three o's on the left there's only two on the right so we need to balance this somehow and the way we can do this is maybe there now we've got four o's on the right but we have two ends as well and so we need to have two ends on the left and now this should be balanced we've got two and o's one o2 and that's gonna make two n o two because we've got two nitrogen and four oxygens in both sides the next step is to figure out well how much do we have that everything.

01:01 So if we just straight up go and count how much no molecules and how much o2 molecules do we have.

01:08 The no, we've got one, two, three, four, five, six, seven, eight.

01:14 Hopefully you're able to count eight as well.

01:16 I'm some wrong.

01:18 And then for o2, we've got one, two, three, four, and five.

01:23 So we've got five, oh two.

01:25 When we look at this reaction, we've got eight n0, 502, how much can we do? well, if we look, if we have 8 no as a limiting reactant, we can do four reactions because we need two of them to do a reaction.

01:39 If we have 502 as the limiting reactant, well, we can do five reactions, which would require we need 10 nos because we need 2 no, sorry, nitrogen monoxide for every reaction that we do, whereas we only need 1 -02.

01:54 So in this case, no, nitrogen monoxide, is limiting because we need twice as many as the oxygen and we don't have.

02:05 So knowing that this is the limiting reaction, we can see, well, assuming we have eight nos, we can still do four reactions because we use two nos for each reaction.

02:15 And so four reactions is going to give us eight molecules of nitrogen dioxide...

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