Given the following DNA coding strand 5' ACT ATG CCC CCT ACA...

Given the following DNA coding strand 5' ACT ATG CCC CCT ACA 3'. The amino acid sequence is: THE GENETIC CODE SECOND LETTER U C A G U UUU Phe UCU Ser UAU Tyr UGU Cys U UUC UAU UAC UGC C UUA Leu UCA UAA Ochre (terminator) UGA Opal terminator A UUG UCG UAG Amber (terminator) UGG Trp G C CUU Leu CCU Pro CAU His CGU Arg U CUC CCC CAC CGC C CUA CCA CAA Gln CGA A CUG CCG CAG CGG G A AUU Ileu ACU Thr AAU Asn AGU Ser U AUC ACC AAC AGC C AUA ACA AAA Lys AGA Arg A AUG Met (initiator) ACG AAG AGG G G GUU Val GCU Ala GAU Asp GGU Gly U GUC GCC GAC GGC C GUA GCA GAA Glu GGA A GUG (initiator) GCG GAG GGG G Ala-Leu-Trp-Asp-Val Ser-Met-Ala-Arg-Thr Met-Gly-Thr-Arg-Met Thr-Met-Pro-Leu-Thr Thr-Met-Pro-Pro-Thr

Transcript

00:01 We've been given the coding strand of dna.

00:03 We want to know what the amino acid sequence will be.

00:06 Okay, so we've got the sequence.

00:08 First of all, we need to know what to do with this coding strand, because there are two strands of dna.

00:14 There's the coding, which is what we've been given, and this is the template.

00:19 So how do we go from dna to m rna here? well, m rna is based on the template.

00:34 So when this dna is transcribed, the strands we're given isn't one being transcribed.

00:41 This one is.

00:42 So the mrna is complementary to the template.

00:46 The coding strand is also complementary to the template.

00:49 So if we go from dna to mrn first, it's actually very easy for us.

00:56 Because, so, mrna is complementary to template, coding also complementary, the coding strands and the mrna look very similar.

01:06 The only thing we have to remember is the rna, uses uricil nuthymein.

01:11 So let's replace, let's just do the same thing except replace the uricil instead of the thymine.

01:24 Ccu a -c -a -3 -prime.

01:27 There we go.

01:28 Now what do we do? so we have five codons here.

01:35 Where do we go from here? well, you've labelled the answer that starts with methionine.

01:43 But methionine isn't the first code on here.

01:45 So typically, if you're looking at translation, what happens is the ribosome scans the mrna, and it stops at the first start codon, and it starts translation there.

01:58 So if this were the real world, yeah, you would start with the metheneene, because that's the first start codon...

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