Question

Let $f(x) = 3x^2 + 11x - 2$. Using the definition of derivative, $f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}$, enter the expression needed to find the derivative at $x = 4$. $f'(x) = \lim_{h \to 0}$ After evaluating this limit, we see that $f'(x) = \frac{df}{dx}$ Finally, the equation of the tangent line to $f(x)$ where $x = 4$ is

          Let $f(x) = 3x^2 + 11x - 2$.
Using the definition of derivative, $f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}$,
enter the expression needed to find the derivative at $x = 4$.
$f'(x) = \lim_{h \to 0}$ 
After evaluating this limit, we see that $f'(x) = \frac{df}{dx}$ 
Finally, the equation of the tangent line to $f(x)$ where $x = 4$ is

Let f(x) = 3x^2 + 11x - 2.
Using the definition of derivative, f'(x) = limh → 0(f(x+h) - f(x))/(h),
enter the expression needed to find the derivative at x = 4.
f'(x) = limh → 0
After evaluating this limit, we see that f'(x) = (df)/(dx)
Finally, the equation of the tangent line to f(x) where x = 4 is

Added by James A.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

10/10/2022

Step 1

Step 1: The given function is f(x) = 3x + 11x - 2. Show more…

Show all steps

Thanks for your feedback!

Texts: Left = 3x + 11x - 2 f(x + h) - f(x) / h. Enter the expression needed to find the derivative at 4. f'(x) = lim(h->0) [f(x + h) - f(x)] / h After evaluating this limit, we see that f'(x) = d(f(x)) / dx Finally, the equation of the tangent line to f at x = 4 is