The NIH is creating a test for the Zika virus. The incidence...

The NIH is creating a test for the Zika virus. The incidence of a Zika is low, 6 percent in the general population. There is a trial version, but it sometimes misses the disease. The probability of a false negative is 13 percent. Similarly, someone who does not have Zika, will sometimes get a positive reading. The probability of this is 10 percent. Fill in the tree diagram and ... Answer in percent to 2 decimal places. Marginal Probabilities Conditional Probabilities Joint Probabilities % P(D) P(positive | D) P(negative | D) False negative P(D and positive) P(D and negative) P(no D) P(positive | no D) False Positive P(negative | no D) P(no D and positive) P(no D and negative) Calculate the probability that a positive test result means someone has Zika. % Submit Question

Transcript

00:01 Hi, i'm david and i'm here to help you answer your question.

00:03 Now in this question we're going to discuss about the tree diagram and let me formally the tree here.

00:11 We will have the two cases that we will have either the subject who have the disease or no disease and we call this as a d stand for the dz.

00:20 This is a no disease and we put it as the d no d and then we are told that only the 5 % of the population will get the disease so we want to put it in as a percentage so equal to the 5 % and the no disease will be the 95 % and then after that we will take we'll turn the test and the result can be the positive this one will be the probability of the pontiff until i will not denote by the b given that will be the disease to be the probability in the negative given that will be the disease and here we have the probability under positive given that will be no disease then probability of the negative given that will be no disease and here we are told that this case here will be the false negative and this only be the phone's postules and then we want to find the probability here we told that the probability here we told that the probability the phone negative equal to the 3%.

01:48 So this one will be equal to the 3%.

01:53 And then the common, it will be equal to the 97%.

01:59 And the next one, we were told on the phones, probability of phones negative equal to that.

02:07 And then we have similarly someone who does not have the zika.

02:14 It will sometimes get the positive result that will be the phone positive equal to the 30 % so this one will equal to the 30 % and then the common equal to the 70 % and after that we have to find the john probability and the john probability for the first box here but you need to multiply them like a pair and then we take the 0 .5 % we will times with the 97%.

03:03 And if we compare it, we should get 7 .97, get equal to the 4 .85%.

03:12 And then the next one, for this one, we will take this one here, and then we will have the 5%.

03:21 We times in the 3%.

03:24 And then we get equal to.

03:28 Here, here...

Question

Please give Ace some feedback