The water is flowing through a pipe having diameters 40 cm and 21 cm at sections 1 and 2 respectively. The rate of flow through the pipe is 45 liters/s. Section 1 is 7 m above datum and section 2 is 4.5 m above datum. If the pressure at section 1 is 35 N/cm^2, find the following by neglecting losses: (1) Area of cross section of section 1 (unit in m^2)? (2) Area of cross section of section 2 (unit in m^2)? (3) Velocity head at section 1 (unit in m)? (4) Velocity head at section 2 (unit in m)? (5) Difference in datum head (unit in m)? (6) Pressure head at section 1 (unit in m)? (7) Pressure at section 2 (unit in N/m)?
Added by Jeffrey J.
Step 1
To convert to meters, we divide by 100, so the radius is 0.2 m. The area of a circle is given by the formula $A = \pi r^2$, so the area of cross section of section 1 is: $A_1 = \pi (0.2)^2$ $\boxed{A_1 = 0.04\pi \text{ m}^2}$ Show more…
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