2) Use calculus and algebra to find the equation of the tangent line to $y = \frac{2}{1 + e^{-x}}$ at $x = 0$. Put your final answer in slope intercept form. Be sure to show ALL steps.
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y = 2/(1+e^(-x)) y' = (2(1+e^(-x)) - 2(-e^(-x)))/(1+e^(-x))^2 = (2 + 2e^(-x) + 2e^(-x))/(1+e^(-x))^2 = (2 + 4e^(-x))/(1+e^(-x))^2 Show more…
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