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In this question, we are asked to solve the given system of linear equations.
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First, let's write down an augmented matrix of this system.
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The first row is going to be 1, negative 2, 3 and 16.
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The second row is going to be 2, 1, 1 and 7, and the last row is going to be negative 3, 2, negative 2 and negative 19.
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Now we need to reduce this matrix to a row echelon 4.
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So the first step would be to multiply the second row by the first row by negative 2 and add it to the second row.
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And to multiply the first row by 3 and add it to the third row.
00:57
So in the first, we're just going to rewrite the first row.
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In the second row we are going to get 0.
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5, negative 6 plus 1 is going to be negative 5.
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And negative 32 plus 7 is going to be negative 25.
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And in the last row we are going to get 0.
01:24
Negative 6 plus 2 is negative 4...