Question

Use Newton's method to estimate the one real solution of $x^3 - 4x - 5 = 0$. Start with $x_0 = 0$ and then find $x_2$.

Name: Use Newton's method to estimate the one real solution of x^3 - 4x - 5 = 0. Start with x0 = 0 and then find x2.
Uploaded: 2023-11-20T22:22:00-08:00
Duration: 3 min 24 s
Channel: Zhumagali Shomanov
Description: Use Newton's method to estimate the one real solution of x^3 - 4x - 5 = 0. Start with x0 = 0 and then find x2.

          Use Newton's method to estimate the one real solution of $x^3 - 4x - 5 = 0$. Start with $x_0 = 0$ and then find $x_2$.

Added by Francisco Javier L.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

11/20/2023

Step 1

The derivative is f'(x) = 3x^2 - 4. Show more…

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Use Newton's method to estimate the one real solution of x^(3)-4x-5=0. Start with x_(0)=0 and then find x_(2) Use Newton's method to estimate the one real solution of x3 -- 4x -- 5 = 0. Start with Xo = 0 and then find X2