00:01
In this problem, we're asked to give the formula for a number of compounds.
00:05
So we're just going to start at the top and work our way forward.
00:08
The first one is ammonium -hydrogen phosphate.
00:11
So we're going to start by writing each the ions here.
00:14
So we have ammonium.
00:15
Then we have hydrogen phosphate, h -p -o -4.
00:19
Now, we have to consider the charge on each of these ions by default.
00:30
So the phosphate ion has a 3 minus charge with a hydrogen on it that makes it a 2 minus charge.
00:36
The ammonium ion has a single plus charge.
00:39
So we're actually going to need two ammoniums to counteract the charge on the hydrogen phosphate ion.
00:47
Next one is mercury 1 sulfide.
00:49
So it mercury and sulfur.
00:53
And sulfur has a 2 minus charge.
00:55
Mercury 1 has a 1 plus charge.
00:57
So we're going to need two mercuries to counteract the charge.
01:00
See, we have silicon dioxide.
01:02
So, silicon and dioxide.
01:06
Dioxide means there are two.
01:08
This is not an ionic compound, so that is done as is.
01:13
Next one is sodium sulfite.
01:15
So we have sodium and the sulfite ion.
01:21
Now, the sulfite ion has a charge of three minus, or sorry, two minus.
01:30
So we are going to need two sodiums to offset it because sodium has a one plus charge.
01:40
In letter e, we're asked about aluminum hydrogen sulfate...