A Schottky diode at $T=300 \mathrm{~K}$ is formed with $\mathrm{Pt}$ on $\mathrm{n}$ -type silicon with a doping concentration of $N_{d}=5 \times 10^{15} \mathrm{~cm}^{-3}$. The barrier height is found to be $\phi_{B n}=0.89 \mathrm{~V}$. Determine $($ a $) \phi_{n},(b) V_{b i},(c) J_{s T}$, and $(d) V_{a}$ such that $J_{n}=5 \mathrm{~A} / \mathrm{cm}^{2}$. (Neglect the barrier lowering effect.)