00:01
This seems very similar to the previous problem.
00:06
So first i want to start with the direction ab, r vector for ab, is going to be, in the x direction it's going negative 1 .5 feet.
00:32
In the y direction, it's going positive 3.
00:35
And in the z direction is going positive 1.
00:48
Uab is therefore going to be negative 1 .5i plus 3j plus 1k over the square root of 1 .5 squared plus 3 squared which is 9 plus 1 squared which is 1 .2.
01:16
So that would actually be 12 .25.
01:21
Okay.
01:24
I also need u sub -f, although i'm just going to put f in its component form.
01:48
So the projection of f onto the x, y plane, is going to be f, which is 90 pounds, times the cosine of 60.
02:09
And the cosine of 60 is just one half.
02:15
So that's just going to be 45 pounds.
02:21
Now, f vector form is going to be that 45 pounds times, well, it's 45 degrees in the y direction and the x direction.
02:43
But x is going negative and y is going positive.
02:48
So it's going to be square root of 2 over 2 times 45.
02:56
And in the x direction, it's going negative.
03:01
Same thing, it's going positive in the y direction.
03:09
And in the z direction, we get 90 times the sign of 60.
03:23
The sign of 60 is a square root of 3 over 2.
03:39
So, f in the ab direction is force f dot vector uab...