Light of wavelength 630 nm is incident on a single slit with width 0.40 mm . The figure shows th

step 1 The diffraction pattern looks like here is a bright fringe corresponding to m equals 0. Then the

Light of wavelength 630 nm is incident on a single slit with...

Light of wavelength $630 \mathrm{nm}$ is incident on a single slit with width $0.40 \mathrm{mm} .$ The figure shows the pattern observed on a screen positioned $2.0 \mathrm{m}$ from the slit. Determine the distance from the center of the central bright fringe to the second minimum on one side. (FIGURE CANNOT COPY)

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Single-slit Diffraction

Single-slit diffraction refers to the phenomenon occurring when light passes through a narrow aperture whose width is comparable to the wavelength of the light. This causes the light waves to bend and interfere with each other, producing a characteristic pattern of bright and dark fringes on a distant screen. The analysis of such patterns is fundamental in understanding wave behavior and interference effects.

Diffraction Minima Condition

The positions of the dark fringes (minima) in a single-slit diffraction pattern are determined by the condition a sin? = m?, where 'a' is the slit width, '?' is the wavelength of the light, 'm' is an integer (excluding zero), and ? is the diffraction angle corresponding to the minima. This formula is essential for calculating the angular displacement of the minima from the central maximum.

Small Angle Approximation

When diffraction angles are small, the small angle approximation (sin? ? tan? ? ?, where ? is in radians) is used to simplify the conversion between angular positions and linear distances on the screen. This approximation enables the estimation of the position of the fringes by relating the diffraction angle to the distance on the screen using the relation y ? L?, where 'L' is the distance from the slit to the screen.

Transcript

Please give Ace some feedback