Find a parametrization of the line in which the planes x - 3y + 3z = - 7 and - 2x + 2y - 2z = 2 intersect. Find the parametrization of the line. Use a point with z = 0 on the line to determine the parametrization. x = ? ?, y = ? ?, z = ? ?, - ? < t < ?
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Set z = 0 in x - 3y = -7 and -2x + 2y = 2. From -2x + 2y = 2 => -x + y = 1 => y = x + 1. Substitute: x - 3(x+1) = -7 => -2x - 3 = -7 => x = 2, y = 3. So point P = (2,3,0). Show more…
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