To find $f'(x)$, we need to use the chain rule. The chain rule states that if $f(x) = g(h(x))$, then $f'(x) = g'(h(x)) \cdot h'(x)$.
In this case, let $g(u) = \sin(u)$ and $h(x) = x^5$.
Then $f(x) = g(h(x)) = \sin(x^5)$.
First, find the derivative of $g(u)$
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